IsMenu()

语法

Result = IsMenu(#Menu)
概要
Tests if the given menu is valid and correctly initialized.

参数

#Menu The menu to test.

返回值

Nonzero if the menu is valid, zero otherwise.

Remarks

This function is bulletproof and may be used with any value. This is the correct way to ensure a menu is ready to use.

参阅

CreateMenu(), CreatePopupMenu(), CreateImageMenu(), CreatePopupImageMenu()

已支持操作系统

所有

<- HideMenu() - Menu Index - MenuBar() ->